题解 | 牛牛的金币
牛牛的金币
https://www.nowcoder.com/practice/35d8e3e569dc49f2a1018d1dc9186998
#include <stdio.h>
//嘻嘻很简单哦!!!!!!!!!!!!!!!!!!!!!!
int main()
{
int x,y,x1,y1;
scanf("%d %d\n%d %d",&x,&y,&x1,&y1);
if(x-x1==0&&y1>y){
printf("u");
}else if(x-x1==0&&y1<y){
printf("d");
}else if(x>x1&&y-y1==0){
printf("l");
}else if(x<x1&&y-y1==0){
printf("r");
}
}


