题解 | 字符个数统计
字符个数统计
https://www.nowcoder.com/practice/eb94f6a5b2ba49c6ac72d40b5ce95f50
关键点在于每个字符只统计一次
很明显需求就是去重，使用stl的set
#include <bits/stdc++.h>
using namespace std;
#define int long long
const int N = 2e5 + 5;
int __t = 1, n;
void solve() {
string s;
cin >> s;
set<char> st;
for (char c : s) {
st.insert(c);
}
cout << st.size() << "\n";
}
int32_t main() {
#ifdef ONLINE_JUDGE
ios::sync_with_stdio(false);
cin.tie(0);
#endif
//cin >> __t;
while (__t--)
solve();
return 0;
}
