题解 | KiKi和酸奶
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
int main()
{
int n = 0;
int m = 0;
int h = 0;
scanf("%d %d %d",&n,&h,&m);
printf("%d\n", (n * h - m) / h);
}
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
int main()
{
int n = 0;
int m = 0;
int h = 0;
scanf("%d %d %d",&n,&h,&m);
printf("%d\n", (n * h - m) / h);
}
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