题解 | 2的n次方计算
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h> int main() { int n = 0; scanf("%d\n", &n); printf("%d\n", 2 << (n - 1)); return 0; }
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h> int main() { int n = 0; scanf("%d\n", &n); printf("%d\n", 2 << (n - 1)); return 0; }
相关推荐