题解 | 2的n次方计算
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h>
int main()
{
int n = 0;
scanf("%d\n", &n);
printf("%d\n", 2 << (n - 1));
return 0;
}
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h>
int main()
{
int n = 0;
scanf("%d\n", &n);
printf("%d\n", 2 << (n - 1));
return 0;
}
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