题解 | 链表中倒数最后k个结点
链表中倒数最后k个结点
https://www.nowcoder.com/practice/886370fe658f41b498d40fb34ae76ff9
/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param pHead ListNode类 * @param k int整型 * @return ListNode类 */ ListNode* FindKthToTail(ListNode* pHead, int k) { // write code here //空链表检测 int listLength = 0; if(pHead != nullptr) listLength++; else return nullptr; //计算链表长度 auto head = pHead; auto current = head; while (current->next != nullptr) { current = head->next; head = current; listLength++; } //链表长度小于k if(k > listLength) return nullptr; //返回该链表中倒数第k个节点 int index = 0; head = pHead; current = head; while (index++ < listLength-k) { current = head->next; head = current; } return head; } };#链表中倒数K个结点##链表#