题解 | 姓名与学号

my_dict1 = {'name': 'Niuniu', 'Student ID': 1}
my_dict2 = {'name': 'Niumei', 'Student ID': 2}
my_dict3 = {'name': 'Niu Ke Le', 'Student ID': 3}
dict_list = []
dict_list.append(my_dict1)
dict_list.append(my_dict2)
dict_list.append(
    my_dict3)  # 列表结构 {['name':'Niuniu','Student ID':1], ['name':'Niumei', 'Student ID':2], ['name':'Niu Ke Le', 'Student ID':3]}
for i in dict_list:
    print(f"{i['name']}'s student id is {i['Student ID']}.")