题解 | 鸡兔同笼:贪心算法
鸡兔同笼
https://www.nowcoder.com/practice/fda725b4d9a14010bb145272cababef1
#include <iostream>
using namespace std;
int main() {
int n;
while (cin >> n) {
int min=0;
int max=0;
if(n%2==0) //此时一定有解
{
min=n/4+n%4/2;
max=n/2;
}
cout << min << ' ' << max << endl;
}
}
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