题解 | 鸡兔同笼:贪心算法

#include <iostream>
using namespace std;

int main() {
    int n;
    while (cin >> n) {
        int min=0;
        int max=0;
        if(n%2==0) //此时一定有解
        {
            min=n/4+n%4/2;
            max=n/2;
        }
        cout << min << ' ' << max << endl;

    }
}