题解 | 删除字符串中出现次数最少的字符
a=input()
b={}
c=[]
d=[]
e=''
for i in a:
if i not in b:
b[i]=(a.count(i))
continue
for i in b:
c.append(b[i])
for i in b:
if b[i] == min(c):
d.append(i)
for i in a:
if i in d:
continue
else:
e+=i
print(e)
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