题解 | 查找两个字符串a,b中的最长公共子串
short=input()
long1=input()
if len(short)>len(long1):
short,long1=long1,short
list1=[]
for i in range(len(short)):
for j in range(i+1,len(short)):
if short[i:j] in long1:
list1.append(short[i:j])
list2=sorted(list1,key=len,reverse=True)
print(list2[0])
