题解 | 字符串的排列

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param str string字符串 
# @return string字符串一维数组
#
class Solution:
    def Permutation(self, s: str):
        # write code here
        if len(s) <= 1:
            return [s]
        res = list()
        for i in range(len(s)):
            for j in self.Permutation(s[:i] + s[i+1:]):
                res.append(s[i] + j)
        return list(set(res))