题解 | #求最小公倍数#
求最小公倍数
https://www.nowcoder.com/practice/22948c2cad484e0291350abad86136c3
# 解题思路：枚举法，如何降低算法复杂度
a, b = map(int, input().split())
max_ab = max(a, b)
for i in range(max_ab, a * b + 1,max_ab):
if i % a == 0 and i % b == 0:
print(i)
break
虽然我也是抄的