题解 | #简单计算器#

#include<stdio.h>
int main()
{
	double  a,c;
	char b;
	scanf("%lf%c%lf",&a,&b,&c);
	if(b!='+'&&b!='-'&&b!='*'&&b!='/') printf("Invalid operation!");
	switch(b)
	{
	case '+':
		printf("%.4lf+%.4lf=%.4lf",a,c,a+c);
		break;
	case '-':
		printf("%.4lf-%.4lf=%.4lf",a,c,a-c);
		break;
	case '*':
		printf("%.4lf*%.4lf=%.4lf",a,c,a*c);
		break;
	case '/':
		if(c==0) {
			printf("Wrong!Division by zero!");
			return 0;
		}
		printf("%.4lf/%.4lf=%.4lf",a,c,a/c);
		break;
	}
	return 0;
}