题解 | #数字颠倒#
数字颠倒
https://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe
#include <iostream>
#include <string>
using namespace std;
int main() {
int num;
cin>>num;
string s1 = to_string(num);
string s2;
for(int i=s1.size()-1; i>=0; i--)
{
s2+=s1[i];
}
cout<<s2<<endl;
return 0;
}
// 64 位输出请用 printf("%lld")
