题解 | #公共子串计算#

s1 = input().lower()        # 短
s2 = input().lower()        # 长
if len(s1) > len(s2):
    s1,s2 = s2,s1
p = 0
for i in range(len(s1)):
    for j in range(i,len(s1)):
        if (s1[i:j+1] in s2 ) and (j+1-i > p):
            p = j+1-i
print(p)