题解 | #打印每一行出现的数字个数#

#!/bin/bash

awk -F "" 'BEGIN{sum=0}{for(i=1;i<=NF;i++) if($i <= 5 && $i >= 1) a[NR]+=1}END{for(i=1;i<=NR;i++){sum+=a[i];{if(!a[i]){a[i]=0} print ("line"i" number: "a[i])}}print "sum is "sum}' nowcoder.txt