题解 | #n的阶乘#

#include <iostream>
using namespace std;

long long JC(int n)
{
    if(n==1)return 1;
    else
     return n*JC(n-1);
}

int main() {
    int n;
    while (cin >>n) { 
        cout<<JC(n)<<endl;
    }
}