# 题解 | #学英语#

https://www.nowcoder.com/practice/1364723563ab43c99f3d38b5abef83bc

```const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void (async function () {
const objMap = {
1: "one",
2: "two",
3: "three",
4: "four",
5: "five",
6: "six",
7: "seven",
8: "eight",
9: "nine",
10: "ten",
11: "eleven",
12: "twelve",
13: "thirteen",
14: "fourteen",
15: "fifteen",
16: "sixteen",
17: "seventeen",
18: "eighteen",
19: "nineteen",
20: "twenty",
30: "thirty",
40: "forty",
50: "fifty",
60: "sixty",
70: "seventy",
80: "eighty",
90: "ninety",
100: "hundred",
1000: "thousand",
1000000: "million",
100000000: "billion",
};
const objArr = Object.keys(objMap).reverse();
// 拆解数值 获取拆解的数组
function getNumsArr(num) {
const resArr = [];
while (num > 0) {
objArr.some((dividend) => {
dividend = +dividend;
const innerRes = num / dividend;
const innerRemainder = num % dividend;
// 大于1 代表可以分解 从大到小进行除法与取余
if (innerRes >= 1) {
const parseIntInnerRes = parseInt(innerRes);
resArr.push({
// 余数
remainder: innerRemainder,
// 除结果
res: parseIntInnerRes,
// 对应的单位
dividend,
children:
// 对于大于100的需要继续分解
parseIntInnerRes > 100
? getNumsArr(parseIntInnerRes)
: [],
});
// 赋值 达到循环的条件
num = innerRemainder;
// 利用some的特点,减少循环
return true;
}
});
}
return resArr;
}
// 根据拆解的数组格式化展示值
function formaterRes(res) {
return res
.map((item, index) => {
const haveChildren = item.children.length > 0;
if (haveChildren) {
// 大于100的这里还需要加上单位dividend  four hundred and eighty six (针对这里) thousand six hundred and sixty nine
return `\${formaterRes(item.children)} \${
objMap[item.dividend]
}`;
} else {
// 如果是 50 9 这种不用额外加1 这种情况one fifty
if (
item.dividend >= 1 &&
item.dividend < 100 &&
item.res === 1
) {
return `\${objMap[item.dividend]}`;
} else {
return `\${objMap[item.res]} \${objMap[item.dividend]}\${
item.dividend === 100 && res.length - 1 !== index
? " and"
: ""
}`;
}
}
})
.join(" ");
}

while ((line = await readline())) {
let num = +line;
console.log(formaterRes(getNumsArr(num)));
}
})();

```

#题解#

07-31 14:58