先统计每个字符的次数,再遍历到第一个次数为1的字符
找出字符串中第一个只出现一次的字符
https://www.nowcoder.com/practice/e896d0f82f1246a3aa7b232ce38029d4
import java.util.*; // 注意类名必须为 Main, 不要有任何 package xxx 信息 public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); String string = in.nextLine(); char[] charArray = string.toCharArray(); Map<Character, Integer> linkedHashMap = new LinkedHashMap<>(); for (int i = 0; i < charArray.length; i++) { char c = charArray[i]; Integer integer = linkedHashMap.get(c); if (integer == null) { linkedHashMap.put(c, 1); } else { linkedHashMap.put(c, integer + 1); } } boolean ok = false; for (Map.Entry<Character, Integer> entry : linkedHashMap.entrySet()) { if (entry.getValue() == 1) { System.out.println(entry.getKey()); ok = true; break; } } if (!ok) { System.out.println("-1"); } } }