题解 | #有序序列判断#
有序序列判断
https://www.nowcoder.com/practice/22e87f8a8d764a6582710f38d1b40c6e
//BC122 有序序列判断
#include<stdio.h>
void arr_s(int arr[], int n)
{
for (int i = 0; i < n; i++)
{
scanf("%d", &arr[i]);
}
}
void arr_sort(int arr[], int n)
{
int count1 = 0;
int count2 = 0;
for (int i = 0; i < n - 1; i++)
{
if ((arr[i] <= arr[i + 1]))
count1++;
else if ((arr[i] >= arr[i + 1]))
count2++;
}
if (count1 == n - 1 || count2 == n - 1)
printf("sorted\n");
else
printf("unsorted\n");
}
int main()
{
int n = 0;
int arr[100] = { 0 };
scanf("%d", &n);
arr_s(arr, n);
arr_sort(arr, n);
return 0;
}
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