题解 | #[NOIP2008]ISBN号码#
[NOIP2008]ISBN号码
https://www.nowcoder.com/practice/95712f695f27434b9703394c98b78ee5
#include <cmath>
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
int main() {
string ISBN;
cin >> ISBN;
int sum = 0, less;
int o = 1;
int check;
for (int i = 0; i < ISBN.length(); i++) {
if (ISBN[i] >= '0' && ISBN[i] <= '9' && o<=9) {
sum += (ISBN[i] - '0') * o;
o++;
}
}
less = sum%11;
if(ISBN.back()!= 'X')
{
check = ISBN.back()-'0';
if (less==check)
{
cout<<"Right";
}
else{
if (less == 10) {
ISBN.back() = 'X';
} else {
ISBN.back() = '0' + less;
}
cout<<ISBN;
}
}
else{
check = 10;
if (less==check)
{
cout<<"Right";
}
else{
if (less == 10) {
ISBN.back() = 'X';
} else {
ISBN.back() = '0' + less;
}
cout<<ISBN;
}
}
}
感觉有点麻烦了，输入字符串遍历，处理数字字符，累加计算后，检查，注意是不是X
