题解 | #等差数列#
等差数列
https://www.nowcoder.com/practice/f792cb014ed0474fb8f53389e7d9c07f
#include <stdio.h> int main() { int n; scanf("%d",&n); int num; num = (2 + 2 + 3*(n-1))*n/2; printf("%d\n", num); return 0; }
等差数列
https://www.nowcoder.com/practice/f792cb014ed0474fb8f53389e7d9c07f
#include <stdio.h> int main() { int n; scanf("%d",&n); int num; num = (2 + 2 + 3*(n-1))*n/2; printf("%d\n", num); return 0; }
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