题解 | #完全数计算#
完全数计算
https://www.nowcoder.com/practice/7299c12e6abb437c87ad3e712383ff84
#include <stdio.h> int main() { int a, i, j; while (scanf("%d", &a) != EOF) { // 注意 while 处理多个 case // 64 位输出请用 printf("%lld") to int count = 0; for(i=1; i<=a; i++){ int sum = 0; for (j=1; j<=(i/2); j++){ if (i%j==0) sum = sum+j; } if (sum == i) count++; } printf("%d\n", count); } return 0; }