题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
# class ListNode: # def __init__(self, x): # self.val = x # self.next = None # # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param head ListNode类 # @param m int整型 # @param n int整型 # @return ListNode类 # class Solution: def reverseBetween(self , head: ListNode, m: int, n: int) -> ListNode: # write code here dummy = ListNode(-1) dummy.next = head p0 = dummy for i in range(m-1): p0 = p0.next cur = p0.next pre = None for i in range(n-m+1): nxt = cur.next cur.next = pre pre = cur cur = nxt p0.next.next = cur p0.next = pre return dummy.next
将链表内指定区间看作一个整体,对该区间翻转,随后连接头节点和尾节点。