题解 | #Skew数#
Skew数
https://www.nowcoder.com/practice/7b6586ac8f614aafbe2e0896e82ac0c1
def skew(n):
s = 0
i=0
while n:
i += 1
t = n % 10
n = n // 10
s += t * (2**i-1)
return s
while True:
try:
n = int(input())
if n == 0:
break
print(skew(n))
except:
break
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