题解 | #链表的奇偶重排#

package main

import . "nc_tools"
/*
 * type ListNode struct{
 *   Val int
 *   Next *ListNode
 * }
 */

/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param head ListNode类 
 * @return ListNode类
*/
func oddEvenList( head *ListNode ) *ListNode {
    // write code here
    if head == nil || head.Next == nil {
        return head
    }
    odd, even, evenHead := head, head.Next, head.Next
    for even != nil && even.Next != nil {
        odd.Next = odd.Next.Next
        even.Next = even.Next.Next
        odd = odd.Next
        even = even.Next
    }
    odd.Next = evenHead    
    return head
}