题解 | #提取不重复的整数#

#include <iostream>
#include <array>
using namespace std;

int main() {
    int n;
    cin >> n;
    int result = 0;
    array<bool, 10> numbers{false};
    while (n > 0) {
        int v = n % 10;
        n /= 10;
        if (!numbers[v]) {
            numbers[v] = true;
            result = result * 10 + v;
        }
    }
    cout << result << endl;
}