题解 | #数字颠倒#
数字颠倒
https://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe
#include <iostream>
using namespace std;
int main() {
int n{};
cin >> n;
do
{
printf("%d", n % 10);
n /= 10;
} while (n);
return 0;
}
// 64 位输出请用 printf("%lld")