题解 | #提取不重复的整数#

#include <iostream>
using namespace std;

int main() {
    int num;
    int a[10] = {0};
    while (cin >> num ) { // 注意 while 处理多个 case
        while (num / 10) {
            int reminder = num % 10;
            if (a[reminder] == 0) {
                cout << reminder;
                a[reminder] = 1;
            }
            num = num/10;
        }
        if(num > 0 && a[num] == 0) cout << num;
        cout << endl;
    }
}
// 64 位输出请用 printf("%lld")