题解 | #从单向链表中删除指定值的节点#

a = list(map(int,input().strip().split(" ")))
atemp = a[2:-1]
a2,del1 = [a[1]],a[-1]
a3=[]
for i in range(0,len(atemp),2):
    a3.append([atemp[i],atemp[i+1]])
for i in a3:
    if i[1] not in a2:
        b1 = a2.index(i[0])
        if b1 == 0:
            a2 = [i[1]] + a2
        else:
            a2 = a2[:b1] + [i[1]] + a2[b1:]
    else:
        b1 = a2.index(i[1])
        a2 = a2[:b1+1] + [i[0]] + a2[b1+1:]
a2.remove(del1)
for i in a2:
    print(i,end=" ")