题解 | #百钱买百鸡问题#
百钱买百鸡问题
https://www.nowcoder.com/practice/74c493f094304ea2bda37d0dc40dc85b
for k in range(34):
for j in range(100-3*k+1):
if 100-3*k-j>=0:
i=100-3*k-j
if 5*i+3*j+k==100:
res=[i,j,3*k]
print(" ".join(str(i) for i in res))
else:
break
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