题解 | #数字颠倒#
数字颠倒
https://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe
#include <stdio.h>
#include <string.h>
int main() {
int i, len;
char a[30] = {0};
while (scanf("%s", a) != EOF) { // 注意 while 处理多个 case
len = strlen(a);
for (i = len-1; i >= 0; i--) {
printf("%c", a[i]);
}
}
return 0;
}
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