题解 | #从单向链表中删除指定值的节点#

#include<iostream>
#include<vector>
#include<algorithm>
using namespace std;

int main() {
    int n, head;
    while (cin >> n >> head) {
        vector<int> array; //用数组模拟链表
        array.push_back(head);
        for (int i = 1; i < n; i++) {
            int num, pos_num;
            cin >> num >> pos_num; //输入要插入的数和它要插入哪个数字后面
            auto iter = find(array.begin(), array.end(),
                             pos_num); //找到要插入后面你的那个位置
            if (iter == array.end()) //结尾push_back
                array.push_back(num);
            else //中间insert
                array.insert(iter + 1, num);
        }
        int remove;
        cin >> remove;
        array.erase(find(array.begin(), array.end(),
                         remove)); //找到要移除的数字的位置
        for (int i = 0; i < array.size(); i++) //输出
            cout << array[i] << " ";
        cout << endl;
    }
    return 0;
}