题解 | #奇偶统计#
奇偶统计
https://www.nowcoder.com/practice/04de8eb0ecab426fa6be3ae99af17210
#include <stdio.h>
int main() {
int n;
scanf("%d",&n);
if(n%2==0)
{
printf("%d %d\n",n/2,n/2);
}
else {
printf("%d %d\n",n/2+1,n/2);
}
return 0;
}
