题解 | #字符统计#
字符统计
https://www.nowcoder.com/practice/c1f9561de1e240099bdb904765da9ad0
//虽然稍微麻烦一点,但时间和空间上都有所节省,ascii要相对熟练 #define _CRT_SECURE_NO_WARNINGS 1 #include <stdio.h> #include<string.h> int main() { char arr[1000], arr2[36]; scanf("%s", arr); int i = 0, j = 0, p[36] = { 0 }, sz = strlen(arr), num = 0; for (i = 0; i < sz; i++) { if (arr[i] >= '0' && arr[i] <= '9') { p[arr[i]-48]++; num = num > p[arr[i]-48] ? num : p[arr[i]-48]; } else { p[arr[i] - 87]++; num = num > p[arr[i] - 87] ? num : p[arr[i] - 87]; } } for (j = num; j > 0; j--) { for (i = 0; i < 10; i++) { if (p[i] == j) { printf("%d", i); } } for (i = 10; i < 36; i++) { if (p[i] == j) { printf("%c", i + 87); } } } return 0; }