题解 | #二叉树的镜像#
二叉树的镜像
https://www.nowcoder.com/practice/a9d0ecbacef9410ca97463e4a5c83be7
# class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None # # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param pRoot TreeNode类 # @return TreeNode类 # class Solution: def Mirror(self , pRoot: TreeNode) -> TreeNode: # write code here if not pRoot: return root_left = pRoot.left root_right =pRoot.right pRoot.left = self.Mirror(root_right) pRoot.right = self.Mirror(root_left) return pRoot
DP的思想,可以划分为原问题的子问题,根节点的左节点为self.Mirror(root_right),根节点的右节点为self.Mirror(root_left)
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