题解 | #杨辉三角#
杨辉三角
https://www.nowcoder.com/practice/e671c6a913d448318a49be87850adbcc
#include <stdio.h> int main() { int n; scanf("%d", &n); int a[30][30] = {0}; for (int i = 1; i <= n; i++) { for (int j = 1; j <= i; j++) { if (j == 1 || i == j) { a[i][j] = 1; } else { a[i][j] = a[i - 1][j] + a[i - 1][j - 1]; } printf("%5d", a[i][j]); } printf("\n"); } return 0; }