题解 | #数值的整数次方#
数值的整数次方
https://www.nowcoder.com/practice/1a834e5e3e1a4b7ba251417554e07c00
class Solution {
public:
double Power(double base, int exponent) {
//快速幂
if(base == 0) return base;
if(exponent == 0) return 1.0;
double res = 1;
for(int i = 0; i < abs(exponent); ++i) {
res *= base;
}
return (exponent > 0)? res : 1.0/res;
}
};
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