题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h> int main() { int arr[20]={0}; int j=0; float fee=0; scanf("%d\n",&j); for(int i=0;i<j;i++) { scanf("%d ",&arr[i]); } for(int i=0;i<j;i++) { if(arr[i]<=60) fee=fee+0.1; else fee=fee+0.2; } printf("%.1f",fee); }