题解 | #小乐乐与进制转换#
小乐乐与进制转换
https://www.nowcoder.com/practice/242eafef2a704c0ca130d563b7b3ee2d
#include <stdio.h>
#include <math.h>
int main() {
int n;
double sum = 0;
scanf("%d", &n);
for (int i = 0; n > 0; i++) {
sum += (n % 6) * pow(10, i);
n /= 6;
}
printf("%.0lf", sum);
return 0;
}
