题解 | #扑克牌顺子#
扑克牌顺子
https://www.nowcoder.com/practice/762836f4d43d43ca9deb273b3de8e1f4
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# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
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# @param numbers int整型一维数组
# @return bool布尔型
#
class Solution:
def IsContinuous(self , numbers: List[int]) -> bool:
# write code here
numbers.sort()
n = numbers.count(0)
newlist = numbers[n:]
if len(newlist)!=len(set(newlist)):
return False
else:
if newlist[-1]-newlist[0]+1 ==len(newlist):
return True
if newlist[-1]-newlist[0]+1 ==len(newlist)+n:
return True
return False

