题解 | #小乐乐改数字#

#include <stdio.h>

int main()
{
    int n = 0, a = 0, c = 0, d = 0;
    int zu[100] = { 0 };
    scanf("%d", &n);
    while (n)
    {
        a = n % 10;
        n = n / 10;
        zu[c] = a;
        c++;
    }
    for (a = 0;a < c;a++)
    {
        if (zu[a] % 2 == 0)
            zu[a] = 0;
        else
            zu[a] = 1;
    }
    for (a = 0;a < c;a++)
    {
        if (zu[c - 1 - a] == 0 && d == 0)
        {
            if (d == 0 && a == c-1)
                printf("%d", 0);
        }
         
        else
        {
            printf("%d", zu[c-1-a]);
            d++;
        }
    }
    return 0;
}