题解 | #跳台阶#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param number int整型 
# @return int整型
#
class Solution:
    def jumpFloor(self , number: int) -> int:
        # write code here
        if number==1:
            return 1
        if number==2:
            return 2
        if number == 3:
            return 3
        a = 1
        b = 2
        c = 3
        for i in range(3,number):
            a = b 
            b = c
            c =a+b
        return c