题解 | #计算某字符出现次数#

#include <stdio.h>
int main(){
    char str[1000];
    char p;
    scanf("%[^\n]%*c", str);
    scanf("%c",&p);
    int len = 0, form = 0;
    for(int i = 0; i < strlen(str); i ++){
        if(p >= 'a' && p <= 'z'){
            if(p == str[i] || str[i] == p - 32)
                len++;
                }
        else if(p >= 'A' && p <= 'Z'){
            if(p == str[i] || str[i] == p + 32)
                len++;
                }
        else if(p >= '1' && p <= '9')
            if(p == str[i])
                len++;
    }
    printf("%d",len);
    return 0;
}