题解 | #旋转数组的最小数字#
旋转数组的最小数字
https://www.nowcoder.com/practice/9f3231a991af4f55b95579b44b7a01ba
import java.util.*; public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型一维数组 * @return int整型 */ public int ans = -1; public int minNumberInRotateArray (int[] nums) { // write code here int first = 0, rear = nums.length-1; int mid = (first+rear)/2; ans = nums[mid]; binarySearch(nums,first,rear); return ans; } public void binarySearch(int []nums,int first,int rear){ if(first>rear){ return ; } int mid = (first + rear) /2 ; if(nums[mid] < ans){ ans = nums[mid]; } binarySearch(nums,first,mid-1); binarySearch(nums,mid+1,rear); } }