题解 | #公共子串计算#
公共子串计算
https://www.nowcoder.com/practice/98dc82c094e043ccb7e0570e5342dd1b
a,b=input(),input()
while True:
try:
if len(a) > len(b):
a,b = b,a
res=""
for i in range(0,len(a)):
for j in range(i,len(a)):
if a[i:j+1] in b and j+1-i > len(res):
res = a[i:j+1]
print(len(res))
break
except:
break
