题解 | #牛牛的线段#
牛牛的线段
https://www.nowcoder.com/practice/f72c56ed71664af082c921bf79861c85
#include <stdio.h>
#include <math.h>
int main()
{
int x1, x2, y1, y2;
scanf("%d%d", &x1, &y1);
scanf("%d%d", &x2, &y2);
printf("%d", (int)(pow(x1-x2, 2)+pow(y1-y2, 2)));
return 0;
}
