题解 | #【模板】链表#
【模板】链表
https://www.nowcoder.com/practice/97dc1ac2311046618fd19960041e3c6f
import java.util.LinkedList;
import java.util.Scanner;
// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
private static LinkedList<Integer> list = new LinkedList<>();
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
// 注意 hasNext 和 hasNextLine 的区别
final int NUM = in.nextInt();
for (int i = 0; i != NUM; ++i) {
String op = in.next();
if (op.equals("insert")) {
int x = in.nextInt();
int y = in.nextInt();
int indexOfX = list.indexOf(x);
if (indexOfX == -1) {
list.addLast(y);
} else if (indexOfX == 0) {
list.addFirst(y);
} else {
list.add(indexOfX, y);
}
}
if (op.equals("delete")) {
int x = in.nextInt();
list.removeFirstOccurrence(x);
}
}
if (list.isEmpty()) {
System.out.println("NULL");
} else {
for (int x : list) {
System.out.print(x + " ");
}
}
}
}
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