题解 | #特殊乘法#
特殊乘法
https://www.nowcoder.com/practice/a5edebf0622045468436c74c3a34240f
#include <iostream> using namespace std; int main() { string a; string b; int x = 0; cin >> a >> b; for (int i = 0; i < a.size(); ++i) { for (int j = 0; j < b.size(); ++j) { x += (a[i] - 48) * (b[j] - 48);//ASCII对应数字 } } std::cout << x << std::endl; }