题解 | #字符串通配符#

const rl = require("readline").createInterface({ input: process.stdin });

var iter = rl[Symbol.asyncIterator]();

const readline = async () => (await iter.next()).value;

void async function () {

// Write your code here

while(line = await readline()){

const line2 = await readline()

let reg = line.replace(/\*/g,'[A-Za-z\\d]*').replace(/\?/g, '[A-Za-z\\d]')

reg = new RegExp('^'+reg+'$','i')

console.log( reg.test(line2))

}

}()

使用 RegExp将字符串转换为正则表达式，通过第二个参数‘i'使得正则表达式对大小写不敏感