题解 | #整数与IP地址间的转换#

def func1(a):
    b = 0
    c = [0,0,0,0,0,0,0,0]
    d = ''
    while int(a) >= 2**b:
        b = b + 1
    b = b - 1
    for i in range(8)[::-1]:
        if int(a) >= 2**i:
            a = int(a)-2**i
            c[7-i] = 1
    for i in c:
        d = d + str(i)
    return d

def func2(a):
    b = 0
    for i in range(len(a)):
        if int(a[i]) == 1:
            b = b + 2**(len(a)-i-1)
    return b

def func3(a):
    b = 0
    c = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]  
    d = ''
    while int(a) >= 2**b:
        b = b + 1
    b = b - 1
    for i in range(32)[::-1]:
        if int(a) >= 2**i:
            a = int(a)-2**i
            c[31-i] = 1
    for i in c:
        d = d + str(i)
    return d
def func4(a):
    b = []
    c = ''
    for i in range(4):
        b.append(a[i*8:(i+1)*8])
    for i in range(4):
        if i < 3:
            c = c + str(func2(b[i])) + '.'
        else:
            c = c + str(func2(b[i]))
    return c


while True:
    try:
        a = input()
        aa = input()
        b = ''
        lis = a.split('.')
        for i in lis:
            b = b + func1(int(i))
        print(func2(b))
        print(func4(func3(aa)))

    except:
        break